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Total: 3
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ŘH: Sedlákovic děti, pol, 2006-01-02 19:59:14 Reply
hm
ŘH: Sedlákovic děti, Mingan, 2005-10-20 21:25:38 Reply
Děti značím podle sedláka (A nebo B) a podle jejich pořadí (a, b nebo c):

Aa=2Ba
2Aa=Ba+Bb
Aa+Ab=2Ba+2Bb
2Aa+2Ab=Ba+Bb+Bc
Bc=21, Aa=?
-----------------
dosazuji postupně do rovností:

4Ba=Ba+Bb -> 3Ba=Bb
2Ba Ab=2Ba+6Ba -> Ab=6Ba
4Ba+12Ba=Ba+3Ba+21 -> Ba=21/12
Ba=1,75

dosaím
Aa=2*1,75
Aa=3,5
ŘH: Sedlákovic děti, HANA, 2005-04-05 14:21:14 Reply
ch1 - 10 let
d1 - 5 let
d2 - 15 let
ch2 - 30 let
d3 - 80 let
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Total: 3
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