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» Main » Messages 011001100100111111Total: 3
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ŘH: Sedlákovic děti, pol, 2006-01-02 19:59:14 Reply
hm
ŘH: Sedlákovic děti, Mingan, 2005-10-20 21:25:38 Reply
Děti značím podle sedláka (A nebo B) a podle jejich pořadí (a, b nebo c):
Aa=2Ba 2Aa=Ba+Bb Aa+Ab=2Ba+2Bb 2Aa+2Ab=Ba+Bb+Bc Bc=21, Aa=? ----------------- dosazuji postupně do rovností: 4Ba=Ba+Bb -> 3Ba=Bb 2Ba Ab=2Ba+6Ba -> Ab=6Ba 4Ba+12Ba=Ba+3Ba+21 -> Ba=21/12 Ba=1,75 dosaím Aa=2*1,75 Aa=3,5 ŘH: Sedlákovic děti, HANA, 2005-04-05 14:21:14 Reply
ch1 - 10 let
d1 - 5 let d2 - 15 let ch2 - 30 let d3 - 80 let Total: 3
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