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» Main » Messages 110001100111011011Total: 5
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RE: UPDATE: 1996, Karel Buchta,Karlovy Vary, 2008-09-26 08:01:04 Reply
Také jsem tak o 1000 uvažoval.
Našel jsem pouze toto: ODM((19 - 9)^6) = 1000 UPDATE: 1996, Tomáš Vala, 2008-09-25 22:47:11 Reply
Je fakt, že ta 1000 by asi bez mocniny nešla. Opravím to.
RE: RE: ŘH: 1996, Karel Buchta, Karlovy Vary, 2008-09-25 19:58:09 Reply
Skoro bych řekl, že ze zadání použití mocniny vypadlo.
Jujicer měl na mysli: (1 + odm(9))^(odm{9}} + 6 = 70 RE: ŘH: 1996, Tomáš Vala, 2008-09-23 15:49:42 Reply
29 = -1+odm(9)+odm(odm(9)^6) - nesplňuje zadání (použita mocnina ^)
32 = (1/odm(9))×96 - OK 35 = -19+(9×6) - OK 38 = (19/odm(9))×6 - OK 70 = (1+[9])"9"+6 - nerozumím ??? 73 = 19+(9×6) - OK 76 = 1+(9×9)-6 - OK 77 = -19+96 - OK 100 = 1+odm(9)+96 - OK 1000 = (1+9)^(9-6) - nesplňuje zadání (použita mocnina ^) 29 = -1+[9]+[[9]"6"]
32 = (1:[9])x96 35 = -19+(9x6) 38 = 19:[9]x6 70 = (1+[9])"9"+6 73 = 19+(9x6) 76 = 1+(9x9)-6 77 = -19+96 100 = 1+[9]+96 1000 = (1+9)"9-6" Total: 5
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